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21a^2=6a
We move all terms to the left:
21a^2-(6a)=0
a = 21; b = -6; c = 0;
Δ = b2-4ac
Δ = -62-4·21·0
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{36}=6$$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-6}{2*21}=\frac{0}{42} =0 $$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+6}{2*21}=\frac{12}{42} =2/7 $
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